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2 years ago

A recipe calls for 2/3 of a cup of milk for 11 cookies. How many cups of milk are needed to make 66 cookies?

Mathematics

1 answer:

Alecsey [184]2 years ago

5 0

Answer:

4 cups of milk

Step-by-step explanation:

since 66 = 6(11), all you need to do is multiply 2/3 by 6

6(2/3) = 4 cups of milk

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5/10 and 1/6 are equivalent ratios

CaHeK987 [17]

Answer:

1 : 5 2 : 10 3 : 15 4 : 20 5 : 25

Step-by-step explanation:

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2 years ago

Let f(x) = -x-1, h(x) = x-3/3<br> Find (f o h)(-1).

larisa86 [58]

(f o h) = -(x - 3/3) - 1
(f o h) = (-x + 3)/3 - 1
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2 years ago

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1 year ago

At the beginning of each of her four years in college, Miranda took out a new Stafford loan. Each loan had a principal of $5,500

kaheart [24]

Answer:

D. $31,337.27

Step-by-step explanation:

We have that the initial amount of the loan is $5500.

Miranda took the loan for 4 years. So, the total present value is $5500×4 = $22,000.

The rate of interest on the loan is 7.5% i.e. 0.075 and it was for the duration of 10 years.

Also, it is given that the loan was compounded annually.

We have the formula as,

$P=\frac{\frac{r}{n}\times PV}{1-(1+\frac{r}{n})^{-t\times n}}$

i.e. $PV=\frac{P\times [1-(1+\frac{r}{n})^{-t\times n}]}{\frac{r}{n}}$

Substituting the values, we get,

i.e. $PV=\frac{P\times [1-(1+\frac{0.075}{12})^{-10\times 12}]}{\frac{0.075}{12}}$

i.e. $22000=\frac{P\times [1-(1+0.00625)^{-120}]}{0.00625}$

i.e. $22000=\frac{P\times [1-(1.00625)^{-120}]}{0.00625}$

i.e. $22000=\frac{P\times [1-0.4735]}{0.00625}$

i.e. $22000=\frac{P\times 0.5265}{0.00625}$

i.e. $P=\frac{22000\times 0.00625}{0.5265}$

i.e. $P=\frac{137.5}{0.5265}$

i.e. $P=261.16$

Thus, the total lifetime cost to pay of the loans compounded annually = 261.16 × 120 = $31,339.2

Hence, the total cost close to the answer is $31,337.27

7 0

2 years ago

Read 2 more answers

100pts Help rounding!

Semmy [17]

Answer:

Step-by-step explanation:

5 158/559

= 5 + 158/559

= 5 + 0.28264758

= 5.28264758

= 5 (rounded to nearest whole number)

4 0

1 year ago

Read 2 more answers