F(-1) = 2(-1)^2 + 8(-1)
= 2(1) + (-8)
= -6
9/3 =3
(X+7)^2/ (x+7) = x+7
1/x-1
3(x+7)/x-1
3x+21/x-1
Move 4x to the other side
2y=10+4x
Divide both sides by 2y
Y=5+4x
2. X-y=13
Move the first variable to the other side
-y=13+x
Answer:
The probability of getting 3 successive 1's from spinning the spinner 3 times = 0.027
Step-by-step explanation:
The spinner has 4 sides, 1,2,3 and 4
The probability of landing on a 1 = P(1) = 0.3
The probability of landing on a 2 = P(2) = It isn't given
The probability of landing on a 3 = P(3) = x
The probability of landing on a 4 = P(4) = 0.1
If Denzil spins the spinner 3 times, what is the probability of getting 3 successive 1's?
Noting that each spin is independent from one another, the probability of getting 3 successive 1's from spinning the spinner 3 times is given as
P(1) × P(1) × P(1) = 0.3 × 0.3 × 0.3 = 0.027
Hope this Helps!!!
