6
24% =
multiply 25 by this fraction
25 × = = 6
9n + 15 < = 10n + 24
9n - 10n < = 24 - 15
-n < = 9
n > = -9
Answer:hrhdhf end b
Step-by-step explanation:
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Answer:[m, m+d, m+2d, - - - - -, n]
Step-by-step explanation:
We know the formula for arithmetic progression is a_(n) = a_(1) + (n-1)d
Where a_(n) is the nth term of the sequence
a_(1) is the first term of the sequence
n is the number of the term like if we are talking about 7th term so the n is 7.
d is the difference between two successive terms.
For this problem we know our first term that is m, our last term that is n and our difference that is d.
For second term we will use the formula
a_(2) = m + (2-1)d
a_(2) = m + (1)d
a_(2) = m + d
Similarly,
a_(3) = m + (3-1)d
a_(3) = m + (2)d
a_(3) = m + 2d
Answer:
a. H0 : p ≤ 0.11 Ha : p >0.11 ( one tailed test )
d. z= 1.3322
Step-by-step explanation:
We formulate our hypothesis as
a. H0 : p ≤ 0.11 Ha : p >0.11 ( one tailed test )
According to the given conditions
p`= 31/225= 0.1378
np`= 225 > 5
n q` = n (1-p`) = 225 ( 1- 31/225)= 193.995> 5
p = 0.4 x= 31 and n 225
c. Using the test statistic
z= p`- p / √pq/n
d. Putting the values
z= 0.1378- 0.11/ √0.11*0.89/225
z= 0.1378- 0.11/ √0.0979/225
z= 0.1378- 0.11/ 0.02085
z= 1.3322
at 5% significance level the z- value is ± 1.645 for one tailed test
The calculated value falls in the critical region so we reject our null hypothesis H0 : p ≤ 0.11 and accept Ha : p >0.11 and conclude that the data indicates that the 11% of the world's population is left-handed.
The rejection region is attached.
The P- value is calculated by finding the corresponding value of the probability of z from the z - table and subtracting it from 1.
which appears to be 0.95 and subtracting from 1 gives 0.04998