Hello!
Ignore the negative and solve the square root which is 13.
Add the negative with 13 you get -13
Special case is when it is square root of -169 then it will involved with i.
But for this question just solve it directly.
Have a great day!
Answer:
The A option is correct since:
Good luck!
Intelligent Muslim,
From Uzbekistan.
Answer: Sure!
Step-by-step explanation:
:)
Answer:
1/3 and 1.5
Step-by-step explanation:
1,2,3,4,5,6,7,8,9,10,11,12,13,14,15
There are 5 Multiples of 3 on the Spinner and 3 multiples of four.
5/15 is the probability for a multiple of 3 which can be simplified to 1/3
3/15 is the probability for a multiple of 4 which can be simplified to 1/5
Hope this Helps!
Answer:
probability that the other side is colored black if the upper side of the chosen card is colored red = 1/3
Step-by-step explanation:
First of all;
Let B1 be the event that the card with two red sides is selected
Let B2 be the event that the
card with two black sides is selected
Let B3 be the event that the card with one red side and one black side is
selected
Let A be the event that the upper side of the selected card (when put down on the ground)
is red.
Now, from the question;
P(B3) = ⅓
P(A|B3) = ½
P(B1) = ⅓
P(A|B1) = 1
P(B2) = ⅓
P(A|B2)) = 0
(P(B3) = ⅓
P(A|B3) = ½
Now, we want to find the probability that the other side is colored black if the upper side of the chosen card is colored red. This probability is; P(B3|A). Thus, from the Bayes’ formula, it follows that;
P(B3|A) = [P(B3)•P(A|B3)]/[(P(B1)•P(A|B1)) + (P(B2)•P(A|B2)) + (P(B3)•P(A|B3))]
Thus;
P(B3|A) = [⅓×½]/[(⅓×1) + (⅓•0) + (⅓×½)]
P(B3|A) = (1/6)/(⅓ + 0 + 1/6)
P(B3|A) = (1/6)/(1/2)
P(B3|A) = 1/3
