H(t) = Ho +Vot - gt^2/2
Vo = 19.6 m/s
Ho = 58.8 m
g = 9.8 m/s^2
H(t) = 58.8 + 19.6t -9.8t^2/2 = 58.8 + 19.6t - 4.9t^2
Maximun height is at the vertex of the parabole
To find the vertex, first find the roots.
58.8 + 19.6t - 4.9t^2 = 0
Divide by 4.9
12 + 4t - t^2 = 0
Change sign and reorder
t^2 - 4t -12 = 0
Factor
(t - 6)(t + 2) =0 ==> t = 6 and t = -2.
The vertex is in the mid point between both roots
Find H(t) for: t = [6 - 2]/2 =4/2 = 2
Find H(t) for t = 2
H(6) = 58.8 + 19.6(2) - 4.9(2)^2 = 78.4
Answer: the maximum height is 78.4 m
I solved and the mean is 10
C + a = 132.....a = 132 - c
5.10c + 9.60a = 898.20
5.10c + 9.60(132 - c) = 898.20
5.10c + 1267.20 - 9.60c = 898.20
5.10c - 9.60c = 898.20 - 1267.20
-4.50c = - 369
c = -369/-4.50
c = 82 <=== child tickets sold
The perimeter of the large square is 24 and the area is 36 units
the perimeter of the small squares are 4 and the areas are 1 unit.
All together the perimeter is 29 and the area is 38.
Formula: length · width
2 big rectangles:96 + 96 = 192
(12 × 8) · 2
2 smaller rectangles: 72 + 72 = 144
(6 × 12) · 2
2 small rectangles: 48 + 48 = 96
(6 × 8) · 2
Add all 3 numbers:
192 + 144 + 96 = 432
Your answer is D. 432 cm²
Hope this helps :)