500 = 200 + 20h is our equation.
Subtract 200 from both sides
300 = 20h
Divide by 20
300/20 = 15.
It will take 15 hours to get 500 points.
Hope this helps!
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Answer:
420
Step-by-step explanation:
Answer:
x = 500 yd
y = 250 yd
A(max) = 125000 yd²
Step-by-step explanation:
Let´s call x the side parallel to the stream ( only one side to be fenced )
y the other side of the rectangular area
Then the perimeter of the rectangle is p = 2*x + 2* y ( but only 1 x will be fenced)
p = x + 2*y
1000 = x + 2 * y ⇒ y = (1000 - x )/ 2
And A(r) = x * y
Are as fuction of x
A(x) = x * ( 1000 - x ) / 2
A(x) = 1000*x / 2 - x² / 2
A´(x) = 500 - 2*x/2
A´(x) = 0 500 - x = 0
x = 500 yd
To find out if this value will bring function A to a maximum value we get the second derivative
C´´(x) = -1 C´´(x) < 0 then efectevly we got a maximum at x = 500
The side y = ( 1000 - x ) / 2
y = 500/ 2
y = 250 yd
A(max) = 250 * 500
A(max) = 125000 yd²
Answer:
135 cm²
Step-by-step explanation:
The area (A) of a trapezoid is calculated as
A = h(a + b)
where h is the height and a, b the parallel bases
Here h = 9, a = 13 and b = 17 , thus
A = × 9 × (13 + 17)
= 0.5 × 9 × 30
= 135 cm²