How many molecules of water are produced by the combustion of 3.00 g of methane
1 answer:
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Answer: Thus the new volume of the gas is 530 ml
Explanation:
Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.
The combined gas equation is,
where,
= initial pressure of gas = 740 torr
= final pressure of gas = 760 torr
= initial volume of gas = 500 ml
= final volume of gas = ?
= initial temperature of gas =
= final temperature of gas =
Now put all the given values in the above equation, we get:
Thus the new volume of the gas is 530 ml