Answer:
a
0.57g
b
20.52
c
28.5
Explanation:
a
The bottle weighs 80g with tablets
If the bottle alone weighs 23g, the tablets weigh 57g
100 tablets weigh 57g, 1 tablet weighs 0.57g
b
0.57g is one tablet, so to achieve 36 tablets we must multiply by 36
0.57 multiplied by 36 is 20.52
c
To find 50 tablets we can use the same method we used before or a slightly faster method
100 tablets is 57g, so all we have to do is halve to find 50
57 divided by 2 is 28.5
Answer:
<h3>Can you please provide the choices? For now this is all I can give you.</h3>
Explanation:
In thermodynamics, an adiabatic process is a type of thermodynamic process which occurs without transferring heat or mass between the system and its surroundings.Unlike an isothermal process, an adiabatic process transfers energy to the surroundings only as work. It also conceptually supports the theory used to explain the first law of thermodynamics and is therefore a key thermodynamic concept.
1. Amperes, is the SI unit (also a fundamental unit) responsible for current.
2. Δq over Δt technically
Rearrange for Δq
I x Δt = Δq
1.5mA x 5 = Δq
Δq = 0.0075
Divide this by the fundamental charge "e"
Electrons: 0.0075 / 1.60 x 10^-19
Electrons: 4.6875 x 10^16 or 4.7 x 10^16
3. So we know that the end resistances will be equal so:
ρ = RA/L
ρL = RA
ρL/A = R
Now we can set up two equations one for the resistance of the aluminum bar and one for the copper: Where 1 represents aluminum and 2 represents copper
We are looking for L2 so we can isolate using algebra to get:
If you fill in those values you get 0.0205
or 2.05 cm
Explanation:
Let are the number of turns in primary and secondary coil of the transformer such that,
A resistor R connected to the secondary dissipates a power
For a transformer,
...............(1)
The power dissipated through the secondary coil is :
.............(2)
Let are the new number of turns in primary and secondary coil of the transformer such that,
New voltage is :
...............(3)
So, new power dissipated is
So, the new power dissipated by the same resistor is 6400 watts. Hence, this is the required solution.