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2 years ago

2^8-x+16=15 HELLO! How is everyone lately?

Mathematics

2 answers:

Lera25 [3.4K]2 years ago

6 0

Answer:

I’m fine ig,

how are you doin?

Step-by-step explanation : )

alina1380 [7]2 years ago

3 0

Answer:

x = 257

Step-by-step explanation:

2^8 - x + 16 =15

256 - x + 16 = 15

256 + 16 - 15 = x

257 = x

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A(-2,3)

Anika [276]

Answer:

The perimeter of triangle is 19.8 units

Step-by-step explanation:

we know that

The perimeter of triangle ABC is

$P=AB+BC+AC$

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

step 1

Find the distance AB

we have

$A(-2,3),B(3,0)$

substitute in the formula

$d=\sqrt{(0-3)^{2}+(3+2)^{2}}$

$d=\sqrt{(-3)^{2}+(5)^{2}}$

$d_A_B=\sqrt{34}\ units$

step 2

Find the distance BC

we have

$B(3,0),C (-4,-3)$

substitute in the formula

$d=\sqrt{(-3-0)^{2}+(-4-3)^{2}}$

$d=\sqrt{(-3)^{2}+(-7)^{2}}$

$d_B_C=\sqrt{58}\ units$

step 3

Find the distance AC

we have

$A(-2,3),C (-4,-3)$

substitute in the formula

$d=\sqrt{(-3-3)^{2}+(-4+2)^{2}}$

$d=\sqrt{(-6)^{2}+(-2)^{2}}$

$d_A_C=\sqrt{40}\ units$

step 4

Find the perimeter

$P=AB+BC+AC$

substitute the values

$P=\sqrt{34}+\sqrt{58}+\sqrt{40}$

$P=19.8\ units$

4 0

2 years ago

Which pair of funtions is not a pair of inverse functions? please help!!

antiseptic1488 [7]

Answer:

$f(x)=\frac{x}{x+20} , g(x)=\frac{20x}{x-1}$

Step-by-step explanation:

we know that

To find the inverse of a function, exchange variables x for y and y for x. Then clear the y-variable to get the inverse function.

we will proceed to verify each case to determine the solution of the problem

case A) $f(x)=\frac{x+1}{6} , g(x)=6x-1$

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

$x=\frac{y+1}{6}$

Isolate the variable y

$6x=y+1$

$y=6x-1$

Let

$f^{-1}(x)=y$

$f^{-1}(x)=6x-1$

therefore

f(x) and g(x) are inverse functions

case B) $f(x)=\frac{x-4}{19} , g(x)=19x+4$

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

$x=\frac{y-4}{19}$

Isolate the variable y

$19x=y-4$

$y=19x+4$

Let

$f^{-1}(x)=y$

$f^{-1}(x)=19x+4$

therefore

f(x) and g(x) are inverse functions

case C) $f(x)=x^{5}, g(x)=\sqrt[5]{x}$

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

$x=y^{5}$

Isolate the variable y

fifth root both members

$y=\sqrt[5]{x}$

Let

$f^{-1}(x)=y$

$f^{-1}(x)=\sqrt[5]{x}$

therefore

f(x) and g(x) are inverse functions

case D) $f(x)=\frac{x}{x+20} , g(x)=\frac{20x}{x-1}$

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

$x=\frac{y}{y+20}$

Isolate the variable y

$x(y+20)=y$

$xy+20x=y$

$y-xy=20x$

$y(1-x)=20x$

$y=20x/(1-x)$

Let

$f^{-1}(x)=y$

$f^{-1}(x)=20x/(1-x)$

$\frac{20x}{1-x}\neq \frac{20x}{x-1}$

therefore

f(x) and g(x) is not a pair of inverse functions

7 0

2 years ago

Read 2 more answers

What about 11 movie tickets

anygoal [31]

Answer:

Step-by-step explanation:

yes please

3 0

2 years ago

What is the slope Of a line that passes through the points (9,8) and (2,3)?

tresset_1 [31]

$(\stackrel{x_1}{9}~,~\stackrel{y_1}{8})\qquad (\stackrel{x_2}{2}~,~\stackrel{y_2}{3}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{3}-\stackrel{y1}{8}}}{\underset{run} {\underset{x_2}{2}-\underset{x_1}{9}}}\implies \cfrac{-5}{-7}\implies \cfrac{5}{7}$

6 0

2 years ago

Read 2 more answers

What is the domain of the function yx4

lutik1710 [3]

The domain of the function is [-4,∞).

Domain is the set of all the possible inputs for which the function is defined.

The given function is:

y = √x+4

It is a radical function. The function is defined if the expression inside the radical greater than or equal to zero.

x+4≥0

Subtract 4 from both the sides.

x+4-4 ≥ 0-4

x ≥ 4

The domain of the function is:

Domain = {xIx ≥ -4} = [-4,∞)

learn more about Domain here:

brainly.com/question/26098895

#SPJ4

5 0

1 month ago