The system of equations representing these costs are; y = 7.5x and y = 5.5x + 10
<h3>How to find the equation of a line?</h3>
The slope of the first line is;
m = (y2 - y1)/(x2 - x1)
m = (32 - 10)/(4 - 0)
m = 5.5
Now, the first coordinate has a y-intercept of 10. Thus, the equation here for the cost is; y = mx + c = 5.5x + 10
The slope of the second line is;
m = (y2 - y1)/(x2 - x1)
m = (15 - 0)/(2 - 0)
m = 7.5
Now, the first coordinate has a y-intercept of 0. Thus, the equation here for the cost is; y = mx + c = 7.5x + 0 = 7.5x
Thus, the system of equations representing these costs are;
y = 7.5x and y = 5.5x + 10
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The answer for this problem: Option C.
Simplify the equation.
First, distribute the 2 in the left side of the equation.
Resulting in: 2x-6 = (x-1) + 7
Second, remove the parentheses form the right side of the equation (there is nothing to distribute there).
Resulting in: x - 1 + 7
Now simplify the right side of the equation by subtracting the 1 from the 7.
Resulting in: x + 6
Our goal is to isolate the x to the left side, and the numerals to the right side.
With that in mind, add the 6 (from the right side) to both sides. This cancels out the 6 on the right side.
Resulting in: 2x = 12
Lastly, in order to fully isolate the variable (x), we divide both sides by 2.
Resulting in: x = 6
Hope this helps.
Since it is perpendicular to y=3x-1, the slope must be a negative reciprocal.
there the slope of the perpendicular line is
So now we have,
To find b, we use the point that the line passes through and substitute it to the y and x values.
which would give us b=5/3
Therefore, the equation of the line is