Answer:
j(12) = 17
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Algebra I</u>
Step-by-step explanation:
<u>Step 1: Define</u>
j(x) = x + 5
j(12) is x = 12
<u>Step 2: Evaluate</u>
- Substitute in <em>x</em>: j(12) = 12 + 5
- Add: j(12) = 17
Since a polynomial is where we have like terms such as (1 x 10²) and (4 x 10²), we can add these up using the distributive property to get (5 x 10²) but still keep the 10². For example, it's similar to if we had 2x²+3x²=5x². The x² is still there, but we add up the 2 and 3. Similarly, we can add these up for 10^1 and 10^0
I think the answer is probably b or c
The results of the arithmetic evaluations as given in the task content are; 40,42 and 62.
<h3>What are the results of the arithmetic evaluations?</h3>
The arithmetic operations above can be evaluated and simplified as follows;
(11-8)x3+7+27-3 = (3×3)+7+27-3 = 40.
(18÷3)+6+(14-8)x5 = (6)+6+(6)x5 = 42.
(11-7)x6+4+32-4 = (5×6) +4 +32-4 = 62.
Read more on arithmetic evaluations;
brainly.com/question/4694189
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