Answer:
0.6 moles of CaO will produced.
Explanation:
Given data:
Mass of calcium = 23.9 g
Moles of CaO produced = ?
Solution:
Chemical equation:
2Ca + O₂ → 2CaO
Number of moles of calcium:
Number of moles = mass/ molar mass
Number of moles = 23.9 g / 40 g/mol
Number of moles = 0.6 mol
Now we will compare the moles of calcium and CaO.
Ca : CaO
2 : 2
0.6 : 0.6
0.6 moles of CaO will produced.
I think your answer will be B. 273 k
Answer:
75 g
Step-by-step explanation:
<em>Step 1. </em>Calculate the molar mass of CaCO₃
Ca = 40.08
C = 12.01
3O = 3 × 16.00 = <u> 48.00
</u>
Total = 100.09 g/mol
<em>Step 2</em>. Calculate the mass of the pellet
Mass of CaCO₃ = 0.75 mol × (100.09 g/1 mol)
Mass of CaCO₃ = 75 g
