Answer:
95% of the population spent between 16.8 hours to 26.2 hours on social media per month
Step-by-step explanation:
- subtracting 1 from sample size: 83-1= 82
- Note Mean=21.5 and standard deviation=2.5
- Subtracting confidence interval from 1 and dividing by 2: (1-0.95)/2=0.025
- At α=0.025 and dF=82, the t-distribution table gives 1.984
- Divide standard deviation by square root of sample size: 21.5/√83= 2.36
- Multiplying answer in step 4 by answer in step 5: 2.36×1.984= 4.68
- For lower end: 21.5-4.68= 16.82
- for upper end: 21.5+4.68=26.18
Answer:
1,805 kg.
Step-by-step explanation:
We have been given that in 2010, the world's largest pumpkin weighed 1,810 kilograms. An average-sized pumpkin weighs 5,000 grams. We are asked to find the how much the world's largest pumpkin weighs than an average pumpkin.
First of all, we will convert the weight of average pumpkin in kilograms by dividing 5,000 by 1000 as 1 kg equals 1,000 gm.
Now, we will subtract the weight of average pumpkin from world's largest pumpkin's weight.
Therefore, the 2010 world-record pumpkin weighs 1,805 kilograms more than an average-sized pumpkin.
Answer:
9m^2 - 4m - 6
Step-by-step explanation: hope this helps!
Answer:
Counselor's estimate isn't correct.
Step-by-step explanation:
Total number of students in university = 30,600
2% break 3 of the languages
Therefore, 2/100 × 30600 = 612 students break 3 of the languages in the University according to the counselor.
In a random sample of 240 students, 20 break 3 of the languages.
% = 20/240 × 100 = 8.33%
SinceTotal number of students = 30,600
Therefore, 30,600/240 = 127.5
Which means 127.5 × 20 = 2550.
Which means 2550 students break 3 of the languages as against the 612 students stated by the counselor.
The percent would be 560%
