Replace <span><span>f<span>(x)</span></span><span>f<span>(x)</span></span></span> with <span>yy</span>.<span><span>y=<span>x2</span>−1</span><span>y=<span>x2</span>-1
</span></span>Interchange the variables.<span><span>x=<span>y2</span>−1</span><span>x=<span>y2</span>-1
</span></span>Solve for <span>yy</span>.
<span><span>y=<span>√<span>1+x</span></span>,−<span>√<span>1+x</span></span></span><span>y=<span>1+x</span>,-<span>1+x
</span></span></span>Solve for <span>yy</span> and replace with <span><span><span>f<span>−1</span></span><span>(x)</span></span><span><span>f<span>-1</span></span><span>(x)</span></span></span>.
<span><span><span>This is your answer=f<span>−1</span></span><span>(x)</span>=<span>√<span>1+x</span></span>,−<span>√<span>1+x</span></span></span><span><span>f<span>-1</span></span><span>(x)</span>=<span>1+x</span>,-<span>1+x
Hope you have a wonderful day! hope this helps!
</span></span></span>
Answer:
133 fishes
Step-by-step explanation:
Units of food A = 400 units
Units of food B = 400 units
Fish Bass required 2 units of A and 4 units of B.
Fish Trout requires 5 units of A and 2 units of B.
i. For food A,
total units of food A required = 2 + 5
= 7 units
number of bass and trout that would consume food A = 2 x
= 114.3
number of bass and trout that would consume food A = 114
ii. For food B,
total units of food B required = 4 + 2
= 6 units
number of bass and trout that would consume food B = 2 x
= 133.3
number of bass and trout that would consume food B = 133
Thus, the maximum number of fish that the lake can support is 133.
Answer: THE LAST OPTION
Step-by-step explanation:
1. You have the following equation given in the problem:
2. If you multiply both sides of the equation shown above by 6, you obtain the following:
3. When you simplify the equation, you obtain the following equivalent equation:
Answer: A.56 sq. units
Step-by-step explanation:
A=( a+b)h/2
(12+16)4/2
(28)2
56
A=56
A. The ratio of the person's shadow to their height is 6:2 or 3:1, so the height of the shadow is 360/3 or 120 m.
B. The model car's length divided by the ratio to the real car, which is 8.5/0.8 = 10.625 cm long.