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2 years ago

Which of the following describes all of the types of water found in the hydrosphere

Chemistry

1 answer:

ankoles [38]2 years ago

4 0

Answer: all of the water on the Earth

Explanation:

The hydrosphere is made up of all the water that we have on Earth. Included in the hydrosphere are the water that we have underground, those in the Earth's surface, and those that we have in the air.

On Earth, we can find water in the seas, lakes, oceans, streams, rivers etc. Water also comes in form of rain as well.

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Which answer best describes the potential energy diagram for a reaction that takes place in water, if the temperature of the sur

blondinia [14]

D. the potential energy of the reactants is low; the potential energy decreases gradually; then increases slightly.

6 0

2 years ago

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Identify the oxidizing agent and the reducing agent for 4Li(s) + O_2 (g) to 2Li_2O(s).

wolverine [178]

Answer: Li is the reducing agentg and O is the oxidizing agent.

Explanation:

1) The oxidizing agent is the one that is reduced and the reducing agent is the one that is oxidized.

2) The given reaction is:

4Li(s) + O₂ (g) → 2 Li₂O(s)

3) Determine the oxidation states of each atom:

Li(s): oxidation state = 0 (since it is alone)

O₂ (g): oxidation state = 0 (since it is alone)

Li in Li₂O (s) +1

O in Li₂O -2

That because 2× (+1) - 2 = 0.

4) Determine the changes:

Li went from 0 to + 1, therefore it got oxidized and it is the reducing agent.

O went from 0 to - 2, therefore it got reduced and it is the oxidizing agent.

7 0

3 years ago

Read 2 more answers

HELPP! pls

pshichka [43]

Answer:

"2.48 mole" of H₂ are formed. A further explanation is provided below.

Explanation:

The given values are:

Mole of Al,

= 3.22 mole

Mole of HBr,

= 4.96 mole

Now,

(a)

The number of mole of H₂ are:

⇒ $\frac{Mole \ of \ H_2}{3} =\frac{Mole \ of HBr}{6}$

or,

⇒ $Mole \ of \ H_2=\frac{1}{2}\times Mole \ of \ HBr$

⇒ $=\frac{1}{2}\times 4.96$

⇒ $=2.48 \ mole$

(b)

The limiting reactant is:

= $HBr$

(c)

The excess reactant is:

= $Al$

6 0

2 years ago

Write a balanced equation for the complete oxidation reaction that occurs when methane (CH4) burns in air.

Lelechka [254]

Answer: The balanced equation for the complete oxidation reaction that occurs when methane (CH4) burns in air is $CH_{4} + 2O_{2} \rightarrow CO_{2} + 2H_{2}O$ .

Explanation:

When a substance tends to gain oxygen atom in a chemical reaction and loses hydrogen atom then it is called oxidation reaction.

For example, chemical equation for oxidation of methane is as follows.

$CH_{4} + O_{2} \rightarrow CO_{2} + H_{2}O$

Number of atoms present on reactant side are as follows.

C = 1
H = 4
O = 2

Number of atoms present on product side are as follows.

C = 1
H = 2
O = 3

To balance this equation, multiply $O_{2}$ by 2 on reactant side. Also, multiply $H_{2}O$ by 2 on product side. Hence, the equation can be rewritten as follows.

$CH_{4} + 2O_{2} \rightarrow CO_{2} + 2H_{2}O$

Now, the number of atoms present on reactant side are as follows.

C = 1
H = 4
O = 4

Number of atoms present on product side are as follows.

C = 1
H = 4
O = 4

Since, the atoms present on both reactant and product side are equal. Therefore, this equation is now balanced.

Thus, we can conclude that balanced equation for the complete oxidation reaction that occurs when methane (CH4) burns in air is $CH_{4} + 2O_{2} \rightarrow CO_{2} + 2H_{2}O$ .

4 0

2 years ago

30 pts! Sodium and water react according to the following equation. If 31.5g of sodium are added to excess water, how many liter

mihalych1998 [28]

First, calculate the number of moles of sodium present with the given mass,

31.5 g of sodium x (1 mol sodium/ 23 g sodium) = 1.37 mol sodium

It is given in the equation that for every 2mols of sodium, one mol of H2 is produced.

mols of H2 = (1.37 mols sodium)(1 mol H2/ 2 mols sodium)
mols of H2 = 0.685 mols H2

Then, at STP, 1 mol of gas = 22.4 L.

volume of H2 = (0.685 mols H2)(22.4 L / 1 mol)
volume of H2 = 15.34 L

Answer: 15.34 L

3 0

3 years ago