Answer:
2,375 cans
Explanation:
The strategy here is to use the information given to calculate the lethal dosage contained in the number of cans we will compute.
We know the lethal dosage is
Ld = 10.0 g caffeine
and we also know that the oncentration of caffeine is:
2.85 mg/ oz
So our problem simplifies to calculate how many oz will contain the lethal dose, and then given the ounces per can determine how many cans are required.
First convert the lethal dose in grams to mg:
Ld =( 10 g x 1000 mg ) = 10,000 mg caffeine
10,000 mg x ( 1 Oz / 2.85 mg ) = 28,500 oz
28500 oz x ( 1 can/12 oz ) = 2,375 cans
We could also have calculated it in one step using conversion factors:
Number of cans = 10000 mg x 1 oz/ 2.85 mg x 1 can / oz = 2,375 cans
(D)Base has a bitter taste
Answer is .
Explanation: To calculate the mass of 1 Xe-atom , we will require atomic mass of Xe which is 131.29amu.
This atomic mass is the mass of 1 mole of 1 Xe-atom. One mole of Xe-atom is atoms of Xe. We will use this relation to convert Mass of Xe-atom into grams.
=
The chemical reaction would be written as:
2HgO = 2Hg + O2
We use this reaction and the amount of the reactant to calculate for the moles of oxygen produced. THen, we use avogadro's number to convert it to molecules. We do as follows:
12.5 g HgO (1 mol / 216.59 g) (1 mol O2 / 2 mol HgO) ( 6.022x10^23 molecules O2 / 1 mol O2 ) = 1.74x10^22 molecules O2 produced
At a particular temperature, the solubility of He in water is 0.080 M when the partial pressure is 1.7 atm. 4.25 atm is the partial pressure of He would give a solubility of 0.200 M.
<h3>What is Henry's Law ?</h3>
Henry's Law is a gas law states that at a constant temperature the amount of gas that dissolved in a liquid is directly proportional to the partial pressure of that gas.
<h3>What is relationship between Henry's Law constant and Solubility ?</h3>
The solubility of gas is directly proportional to partial pressure.
It is expressed as:
where,
= Solubility of gas
= Henry's Law constant
= Partial pressure of gas
Now put the values in above expression we get
0.080M = × 1.7 atm
= 0.047 M/atm
Now we have to find the partial pressure of He
0.200 M = 0.047 M/atm ×
= 4.25 atm
Thus from the above conclusion we can say that At a particular temperature, the solubility of He in water is 0.080 M when the partial pressure is 1.7 atm. 4.25 atm is the partial pressure of He would give a solubility of 0.200 M.
Learn more about the Henry's Law here: brainly.com/question/23204201
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