The first step in solving this is to substitute x with 3 and y with 2, so that
becomes
Then simply solve using the order of operations.
First exponents (there are no parentheses)
Then multiply and divide
And finally add and subtract
Therefore the value <span>of 1/3 x^2 + 5.2y when x=3 and y=2 is 13.4</span>
Answer:
length, width, and height are (b+2), (b-2), (b+3)
Step-by-step explanation:
Doing what the problem statement tells you to do, you get ...
(b^3 +3b^2) -(4b +12)
= b^2(b +3) -4(b +3) . . . factor each pair of terms
= (b^2 -4)(b +3) . . . write as a product
= (b -2)(b +2)(b +3) . . . use the factoring of the difference of squares
The three factors are (b-2) , (b+2) , and (b+3). We have no clue as to how to associate those with length, width, and height. We just know these are the dimensions of the box.
the answer is 250 cubic inches
Answer:
-|x|=-3
|x|=-3
|-x|=-3
Step-by-step explanation:
Answer: 0.32
Step-by-step explanation: