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1 year ago

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Dr. Seals borrows $15,000 to remodel her backyard. The interest rate is 3%. The interest is compounded twice a year for two year

s. How much is the total she pays? How much is the interest?

2 answers:

ahrayia [7]1 year ago

7 0

Answer:

$1688.26

interest= $188.26

Step-by-step explanation:

jok3333 [9.3K]1 year ago

3 0

188.26 is the answer

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The Johnson twins were born nine years after their older sister. This year, the product of the three siblings ages is exactly 18

KATRIN_1 [288]

Answer: The age of the twins is 10 years.

Step-by-step explanation:

Suppose the age of older sister be x

Let the age of twins sister be x-9, as they are born after 9 years.

Product of their ages be

$x(x-9)(x-9)\\\\=x(x^2-18x+81)\\\\=x^3-18x^2+81x$

Sum of their ages will be

$x+x-9+x-9\\\\=3x-18$

According to question,

$1861+3x-18=x^3-18x^2+81x\\\\x^3-18x^2+81x-3x+18-1861=0\\\\x^3-18x^2+78x-1843=0\\\\x=19$

So, Age of older sister will be 19 years.

Age of the twins will be

$19-9=10\ years$

Hence, the age of the twins is 10 years.

3 0

2 years ago

How many solutions does the equation 4x + 2(x − 5) = 3(2x − 4) have? Group of answer choices infinitely many solutions no soluti

aleksandrvk [35]

Answer:

absolutley no solutions

Step-by-step explanation:

5 0

2 years ago

Drag statements and reasons to each row to show why the slope of the line between P and Q is the same as the slope between Q and

Delvig [45]

hi i know i’m late but to help out any future people, the answer is

Row One: Statement: 3/2=slope Reason: Definition of Slope

Row 2: Statement: 3/2=6/4 Reason: Triangle A is similar to Triangle B

5 0

2 years ago

Read 2 more answers

Simplify the expression.

Marizza181 [45]

$\bf \textit{Cofunction Identities}
\\ \quad \\
sin\left(\frac{\pi}{2}-{{ \theta}}\right)=cos({{ \theta}})\qquad 
\boxed{cos\left(\frac{\pi}{2}-{{ \theta}}\right)=sin({{ \theta}})}
\\ \quad \\ \quad \\
tan\left(\frac{\pi}{2}-{{ \theta}}\right)=cot({{ \theta}})\qquad 
cot\left(\frac{\pi}{2}-{{ \theta}}\right)=tan({{ \theta}})
\\ \quad \\ \quad \\
sec\left(\frac{\pi}{2}-{{ \theta}}\right)=csc({{ \theta}})\qquad 
csc\left(\frac{\pi}{2}-{{ \theta}}\right)=sec({{ \theta}})$

$\bf \\\\
-------------------------------\\\\
sin^2(\theta)+cos^2(\theta)=1\implies cos^2(\theta)=1-sin^2(\theta )
\\\\\\
\boxed{cos(\theta )=\sqrt{1-sin^2(\theta )}}$

$\bf \\\\
-------------------------------\\\\
\cfrac{cos^2\left(\frac{\pi }{2}-x \right)}{\sqrt{1-sin^2(x)}}\implies \cfrac{\left[ cos\left(\frac{\pi }{2}-x \right)\right]^2}{cos(x)}\implies \cfrac{[sin(x)]^2}{cos(x)}\implies \cfrac{sin(x)sin(x)}{cos(x)}
\\\\\\
sin(x)\cdot \cfrac{sin(x)}{cos(x)}\implies sin(x)tan(x)$

6 0

3 years ago

Are the graphs of the lines in the pair parallel? Explain. y = 6x + 9 27x – 3y = –81

olga nikolaevna [1]

For the 2nd equation, you need solve for y to get it by itself so once thats done you get y=9x+27 but since the x values (also the slope) aren't equal, they can't be parallel

7 0

2 years ago

Read 2 more answers