2×4=8
b×b×b= b^3
so putting them together would be
8×b^3
Part A. What is the slope of a line that is perpendicular to a line whose equation is −2y=3x+7?
Rewrite the equation −2y=3x+7 in the form Here the slope of the given line is If is the slope of perpendicular line, then
Answer 1:
Part B. The slope of the line y=−2x+3 is -2. Since then lines from part A are not parallel to line a.
Since both lines are not perpendicular to line a.
Answer 2: Neither parallel nor perpendicular to line a
Part C. The line parallel to the line 2x+5y=10 has the equation 2x+5y=b. This line passes through the point (5,-4), then
2·5+5·(-4)=b,
10-20=b,
b=-10.
Answer 3: 2x+5y=-10.
Part D. The slope of the line is Then the slope of perpendicular line is -4 and the equation of the perpendicular line is y=-4x+b. This line passes through the point (2,7), then
7=-4·2+b,
b=7+8,
b=15.
Answer 4: y=-4x+15.
Part E. Consider vectors These vectors are collinear, then
Answer 5:
The range is 327 the maxim subtract the minimum
Answer:
y = 2/5x - 2
Step-by-step explanation:
Step 1: Write equation
2x - 5y = 10
Step 2: Solve for <em>y</em>
- Subtract 2x on both sides: -5y = 10 - 2x
- Divide both sides by -5: y = -2 + 2/5x
- Rewrite: y = 2/5x - 2
Answer:
y = -3/4x-5/2 and y = 2/3x-1/3
Step-by-step explanation:
y+1 = -3/4(x+2)
y+1 = -3/4x-3/2
y = -3/4x-3/2-1
y = -3/4x-5/2
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y-3 = 2/3(x-4)
y-3 = 2/3x-8/3
y = 2/3x-8/3+3
y = 2/3x-1/3