What is the width of a rectangle with a length of 18 cm and an area of 72 cm²
2 answers:
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Answer: x = 2.65, y = 3.81
Step-by-step explanation:
ABC similar to PQR
1) Find the ratio of corresponding sides
2) Use that ratio to find values for x & y
1) Side AB = 2.76cm & Side PR = <em>y</em><em> </em>cm
Side BC = <em>x</em> cm & Side RQ = 3.66 cm
Side CA = 3 cm & Side QP = 4.14 cm (both lengths given)
Can match 3 to 4.14 & ratio of sides in ABC to PQR= 3 /4.14
Length of sides ABC = 3/4.14 times the length of sides PQR
2) x = (3 / 4.14) * 3.66 = 2.65
Now solve for y, ABC to PQR: 2.76 = (3 / 4.14) (<em>y </em>)
<em>equality property</em> (both sides) & inverse operation to isolate <em>y : </em> . 2.76 ÷ (3 / 4.14) = (3 / 4.14 ) ÷ (3 / 4.14) (<em>y</em><em>)</em>
2.76 * (4.14 / 3) = 3 / 4.14 * (4.14 / 3) (<em>y</em><em>)</em>
(2.76 * 1.38 ) = 3.81 = <em>y</em>
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<em>Scale Factor Method: Determine the Multiplier</em>
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