I would go with a because you need to preview/ survey the content.
It keeps prices fair for consumers who are trying to buy there products.
- R3KTFORGOOD ☕
Answer:
The correct answer is the option D: Total project costs are the lowest.
Explanation:
To begin with, when it comes to the business field and the management area, the "project duration" refers basically to the characteristic that the project management has regarding the duration of it, very commonly expressed in terms of working units like hours, days, weeks, months or years for example. Moreover, there are three major types of project duration that are: "Estimated Project Duration", "Actual Project Duration" and "Remaining Project Duration". And to end up, the point where the duration of the project is opmital is when the total project costs are the lowest of all.
The third step in the organization development process is evaluation.
Organizational development is the research and implementation of practices, systems, and technologies that influence organizational change aimed at transforming organizational performance and culture. Organizational changes are typically initiated by group stakeholders.
Organization Development (OD) is an effort focused on empowering an organization through the coordination of strategy, structure, people, rewards, metrics, and management processes.
Organizational development, often abbreviated as OD, improves existing processes and creates new ones. The idea is to understand how to maximize the effectiveness, potential, and capabilities of people and organizations. The science of OD is a combination of work/organization and adult developmental psychology
Learn more about Organizational development here:brainly.com/question/15278438
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Answer:
Value of x maximising profit : x = 5
Explanation:
Cost : C(x) = x^3 - 6x^2 + 13x + 15 ; Revenue: R(x) = 28x
Profit : Revenue - Cost = R(x) - C(x)
28x - [x^3 - 6x^2 + 13x + 15] = 28x - x^3 + 6x^2 - 13x - 15
= - x^3 + 6x^2 + 15x - 15
To find value of 'x' that maximises total profit , we differentiate total profit function with respect to x & find that x value.
dTP/dx = - 3x^2 + 12x + 15 = 0 ► 3x^2 - 12x - 15 = 0
3x^2 + 3x - 15x - 15 = 0 ► 3x (x +1) - 15 (x + 1) = 0 ► (x+1) (3x-15) = 0
x + 1 = 0 ∴ x = -1 [Rejected, production quantity cant be negative] ;
3x - 15 = 0 ∴ 3x = 15 ∴ x = 15/3 = 5
Double derivate : d^2TP/dx^2 = - 6x + 12
d^2TP/dx^2 i.e - 6x + 12 at x = 5 is -6(5) + 12 = - 30+ 12 = -8 which is negative. So profit function is maximum at x = 5
