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2 years ago

PLz help me answer this

Mathematics

1 answer:

igor_vitrenko [27]2 years ago

6 0

Answer is D
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Find the values of the variables <br> i will give brainliest to anyone who’s right.

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P is 48
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R is 22
S is 24

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2 years ago

How do you write x^3/11 in radical form

valentinak56 [21]

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$\sqrt[11]{x^3}$

Step-by-step explanation:

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A plumber had two pipes. The ratio of the length of the longer pipe to the

expeople1 [14]

Answer:

4.95m

Step-by-step explanation:

Let the length of longer and shorter pipe be x and y respectively..

given,

x/y=9/2...(i)

x-1.65=3y ...(ii)

in eqn ii..

x-1.65=3y

or, x/y - 1.65/y = 3

or, 9/2-1.65/y =3

or, 4.5-3 = 1.65/y

or, y=1.65/1.5

•°• y = 1.1m

now,

x/y = 9/2

or, x/1.1 = 4.5

x= 4.5×1.1

•°• x= 4.95m

thus, the length of the longer pipe is 4.95m

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2 years ago

The figure shown below is composed of a semicircle and a non-overlapping equilateral triangle and contains a hole that is also c

Sloan [31]

Check the picture below.

since we know the radius of the larger semicircle is 8, thus its diameter is 16, which is the length of one side of the equilateral triangle. We also know the smaller semicircle has a radius of 1/3, and thus a diameter of 2/3, namely the lenght of one side of the small equilateral triangle.

now, if we just can get the area of the larger figure and the area of the smaller one and subtract the smaller from the larger, we'll be in effect making a hole/gap in the larger and what's leftover is the shaded figure.

$\bf \stackrel{\textit{area of a semi-circle}}{A=\cfrac{1}{2}\pi r^2\qquad r=radius}~\hspace{10em}\stackrel{\textit{area of an equilateral triangle}}{A=\cfrac{s^2\sqrt{3}}{4}\qquad s=\stackrel{side's}{length}} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{\Large Areas}}{\left[ \stackrel{\textit{larger figure}}{\cfrac{1}{2}\pi 8^2~~+~~\cfrac{16^2\sqrt{3}}{4}} \right]\qquad -\qquad \left[ \cfrac{1}{2}\pi \left( \cfrac{1}{3} \right)^2 +\cfrac{\left( \frac{2}{3} \right)^2\sqrt{3}}{4}\right]}$

$\bf \left[ 32\pi +64\sqrt{3} \right]\qquad -\qquad \left[ \cfrac{\pi }{18}+\cfrac{\frac{4}{9}\sqrt{3}}{4} \right] \\\\\\ \left[ 32\pi +64\sqrt{3} \right]\qquad -\qquad \left[ \cfrac{\pi }{18}+\cfrac{\sqrt{3}}{9} \right]~~\approx~~ 211.38 - 0.37~~\approx~~ 211.01$

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3 years ago

Solve (x + 2 < 5) u (x - 7 > -6)

REY [17]

1. (x + 2 < 5) Subtract two from each side to get (x < 3)

2. (x - 7 > -6) Add 7 to both sides to get (x > 1)

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2 years ago