Answer:
(x,y)→(y,-x)
Step-by-step explanation:
Parallelogram ABCD:
A(2,5)
B(5,4)
C(5,2)
D(2,3)
Parallelogram A'B'C'D':
A'(5,-4)
B'(4,-5)
C'(2,-5)
D'(3,-2)
Rule:
A(2,5)→A'(5,-2)
B(5,4)→B'(4,-5)
C(5,2)→C'(2,-5)
D(2,3)→D'(3,-2)
so the rule is
(x,y)→(y,-x)
The measure of B. would be 63 degrees
i hope i helped
(a). The element a₂₁ is the number of boys enrolled in Lacrosse.
(b). The address is a₁₂.
(c). [196 174]
[136 169]
[214 242]
(d). The matrix represents the number of boys and girls from towns A and B enrolled in different sports classes.
(e). 1.125 A = [108 90 ]
[72 99 ]
[117 135]<span />
Answer:
B
Step-by-step explanation:
You are given two sides and the included angle, so you need to use the law of cosines.
c² = a² + b² - 2ab cos C
c² = 12² + 13² - 2(12)(13)cos 134°
c² = 313 - 312(-0.6947)
c² = 529.733
c = 23.016
Now use the law of sines.
c/sin C = a/sin A
23.016/sin 134° = 12/sin A
sin A = 12 × sin 134° / 23.016
sin A = 0.37504
A = 22.03°
B = 180° - 134° - 22.03°
B = 23.97°
m<A = 22°; m<B = 24°; c = 23 km
Answer: B
Answer:
> a<-rnorm(20,50,6)
> a
[1] 51.72213 53.09989 59.89221 32.44023 47.59386 33.59892 47.26718 55.61510 47.95505 48.19296 54.46905
[12] 45.78072 57.30045 57.91624 50.83297 52.61790 62.07713 53.75661 49.34651 53.01501
Then we can find the mean and the standard deviation with the following formulas:
> mean(a)
[1] 50.72451
> sqrt(var(a))
[1] 7.470221
Step-by-step explanation:
For this case first we need to create the sample of size 20 for the following distribution:
And we can use the following code: rnorm(20,50,6) and we got this output:
> a<-rnorm(20,50,6)
> a
[1] 51.72213 53.09989 59.89221 32.44023 47.59386 33.59892 47.26718 55.61510 47.95505 48.19296 54.46905
[12] 45.78072 57.30045 57.91624 50.83297 52.61790 62.07713 53.75661 49.34651 53.01501
Then we can find the mean and the standard deviation with the following formulas:
> mean(a)
[1] 50.72451
> sqrt(var(a))
[1] 7.470221