Answer:
Explanation:
Kinetic energy is the energy an object possesses due to motion. The formula 1/2 the product of mass and the squared velocity.
We know the baseball's kinetic energy is 105 Joules. It is also traveling at a velocity of 10 meters per second. `
First, convert the units of Joules to make unit cancellation easier later in the problem. 1 Joule (J) is equal to 1 kilogram square meter per square second (kg*m²/s²). The baseball's kinetic energy of 105 J is equal to 105 kg*m²/s².
Now we know 2 values:
Substitute these values into the formula.
Now we need to solve for m, the mass. Solve the exponent.
- (10 m/s)²= 10 m/s * 10 m/s = 100 m²/s²
Multiply on the right side.
The variable, m, is being multiplied by 50 square meters per square second. The opposite of multiplication is division, so we divide both sides by that value.
The units of square meter per square second will cancel out.
The mass of the baseball is <u>2.1 kilograms. </u>
Answer:
F_2 = 20 x 10⁻⁶ N
Explanation:
given,
current in right direction
I₁ = 10 A
I₂ = 5 A
I₃ = 8 A
Length of Wire 2 = 15 cm
distance between wire 1 and wire 2, r₁ = 5 cm
distance between wire 2 and 3 = r₂ = 17 - 5 = 12 cm
Force on wire 2 due to current in wire 1 and wire 2
μ₀ =absolute permeability of free space= 4π x 10⁻⁷ H/m
F_2 = 20 x 10⁻⁶ N
This problem is an exact copy of the other one that I just answered for you, about Grace driving 224 miles.
Only the numbers are different, but the way to solve it is exactly the same.
Answer:
292796435 seconds ≈ 300 million seconds
Explanation:
First of all, the speed of the car is 121km/h = 33.6111 m/s
The radius of the planet is given to be 7380 km = 7380000 m
From the relationship between linear velocity and angular velocity i.e., v=rw, the angular velocity of the car will be w=v/r = 33.6111/7380000 = 0.000000455 rad/s = 4.55 x 10⁻⁶ rad/sec
If the angular velocity of the vehicle about the planet's center is 9.78 times as large as the angular velocity of the planet then we have
w(vehicle) = 9.78 x w(planet)
w(planet) = w(vehicle)/9.78 = 4.55 x 10⁻⁶ / 9.78 = 4.66 x 10⁻⁷ rad/sec
To find the period of the planet's rotation; we use the equation
w(planet) = 2π÷T
Where w(planet) is the angular velocity of the planet and T is the period
From the equation T = 2π÷w = 2×(22/7) ÷ 4.66 x 10⁻⁷ = 292796435 seconds
Therefore the period of the planet's motion is 292796435 seconds which is approximately 300, 000, 000 (300 million) seconds
Answer:
121 Joules
6.16717 m
Explanation:
m = Mass of the rocket = 2 kg
k = Spring constant = 800 N/m
x = Compression of spring = 0.55 m
Here, the kinetic energy of the spring and rocket will balance each other
The initial velocity of the rocket is 11 m/s = u.
v = Final velocity
s = Displacement
a = Acceleration due to gravity = 9.81 m/s² = g
The maximum height of the rocket will be 6.16717 m
Potential energy is given by
The potential energy of the rocket at the maximum height will be 121 Joules
