Answer:
1348 light years.
Step-by-step explanation:
Please find the attachment.
Let x represent the distance between KA-7 and KA-11.
We have been given that the first system, KA-7, is 1200 light years away while the second system, KA-11, is 1700 light years away. Lucy sees an angle of 52 degrees between KA-7 and KA-11.
We can see from our attachment that Lucy, KA-7 and KA-11 forms a triangle and we will use law of cosines to solve for x.
Upon substituting our given values in above formula we will get,
Let us take square root of both sides of our equation.
Therefore, KA-7 and KA-11 are approximately 1348 light years apart.
Nope.
They don't meet the requirements of the triangle inequality.
2.1 + 4 = 6.1 < 7.9
The triangle inequality requires the sum of any two sides be greater than the third side.
You multiply the area of the triangle by 2
Answer:
Step-by-step explanation:
Birth Rate in 1994 = 14.6 births per thousand population.
Birth Rate in 2004 = 14.32 births per thousand population.
A linear equation is of the form: y=mx+c
Where:
- x=years after 1994
- y=the birth rate
- m=Yearly Birth Rate
First, we determine the birth rate per year
Therefore, a linear equation that relates y in terms of x is of the form:
When x=0, y=14.6
14.6=-0.028(0)+c
c=14.6
Therefore, the linear equation that relates y in terms of x is:
The Area of the platform is 33m²
Step-by-step explanation:
As the question says, the height of vertex from the base (D from AB) is 7m whereas the height of left vertex from the base (E from AB) is 4m
Thus it means the height of the Δ DCE (DX)= 7-4 ⇒3m
Since the platform is five-sided, the figure can be broken down into constituting parts
- Parallelogram ║ABCE
- Δ DCE
Are of the figure= Area of ║ABCE+ area Δ DCE
Area of ║ABCE= breadth * height
= 6*4 ⇒24m
²
Area Δ DCE= ½*(base)(height)
Putting the value of base is 6m and height as 3m
Area Δ DCE= ½*6*3
=9m
²
Total area= 24+9= 33m
²