We know that:
∠ABC=∠BCA=xº
∠BDC=∠BCD=xº
1) we have to find the angle ∠DBC:
∠BDC+∠BCD+∠DBC=180º
xº+xº+∠DBC=180º
2xº+∠DBC=180º
∠DBC=180º-2xº
2) we have to find the angle ∠ABD:
∠ABD=∠ABC-∠DBC
∠ABD=xº-(180º-2x)
∠ABD=xº-180º+2xº
∠ABD=3xº-180º
Answer: ∠ABD=3xº-180º
Answer:0
Step-by-step explanation:
Answer:
82.5 km
Step-by-step explanation:
Given:
Cross-multiply.
2x = 11(15)
Divide both sides by 2 and solve for x.
x = 82.5 km
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Answer:
9.37 divide by two = 4.685
4.685 in 2DP = 4.68
Step-by-step explanation:
i hoped this helps.
Answer:7yd
Step-by-step explanation: