D. a membrane bound nucleus , lmk if im right
Explanation:
Below is an attachment containing the solution.
So power is considered as the rate of doing work. Base on the problem given, my analysis is that the machine who finish the work faster is machine C. Therefore, in order to finish the same amount of work in a short period of time you are going to expend the most power. My answer is Machine C.
Answer:
-use the exact same equipment
-use the exact same measurements (dropping height)
Explanation:
Answer:
A certain battery can power a 100 Ohm-resistance device for 4 hours. How long can the battery power a 200 Ohm device? Ans: 8 ohms
Part B)
If you put two of these batteries in series with each other - still powering a device with the original 100 Ohm resistance - how long would the batteries last? (Note: you have two batteries now, so twice the energy to begin with than with one battery.)
t₁=8hr
t₂=2hr
Explanation:
Given that,
R₁ =100Ω
R₂ =200Ω
t₁ =4hr
Part A
The expression for energy dessipated across a resistor when it is connected with a single resistor (R) is
Here V is the voltage across the source, t is time
energy dissipated across 200ohms is the same as energy dissipated across 100ohms
rearrange the above equation t₂
Part b
Now two batteries are in series
total emf =2V
use the equation below