Let ∠RTS=∠RST = a (say)
∠QUA=∠QSU= b(say)
then we know , at point S, a+40+b=180. so, a+b=140 we'll use this later.
consider trianglePQR, ∠P+∠Q+∠R=180
i.e.P+(180-2b)+(180-2a)=180
P+180+180-2(a+b)=180 ⇒P+180-2(a+b)=0 ⇒P=2(140)- 180=280-180=100
hence,answer is E
The slope-intercept form is y = mx + b.
Following that kind of form becomes
2y = -8x + 1
y =(-8x + 1)/2
y = -4x + 1/2
Hope this helps <span>✌️</span>☺️✌️
You have the answer if you just do a little bit more but other than that you have your answer
The formula of an area of a circle:
r - a radius
We have r = 14m. Substitute:
If you want an approximate area, you can accept
Then:
You have to subtract 4 from 7 and then add 5 and 3 then add 8 and 2 then multiply 10 with 3 to get 30.