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Answer:
Fundamental frequency in the string will be 25 Hz
Explanation:
We have given length of the string L = 1.2 m
Speed of the wave on the string v = 60 m/sec
We have to find the fundamental frequency
Fundamental frequency in the string is equal to , here v is velocity on the string and L is the length of the string
So frequency will be equal to
So fundamental frequency will be 25 Hz
While plane is moving under tailwind condition it took time "t"
so here we will have
here net speed of the plane will be given as
similarly when it moves under the condition of headwind its net speed is given as
now time taken to cover the distance is 2 hours more
now solving two equations
solving above for v_w we got
Answer:
λ = 596 nm.
Explanation:
Fringe width = λ D / d
λ is wave length , D is screen distance and d is slit separation.
Putting the values
1.62 x 10⁻² =( λ x 5.3 ) / .195 x 10⁻³
λ = 596 nm.