Answer:
2.288 Moles of NH₄NO₃
Explanation:
The Balance chemical equation is as follow:
(NH₄)₂CO₃ + 2 HNO₃ → 2 NH₄NO₃ + H₂O + CO₂
To solve this problem we will do following steps:
Finding moles of Ammonium Carbonate:
As we know,
Moles = Mass / M.Mass
So,
Moles = 110 g / 96.08 g/mol
Moles = 1.144 moles
Calculating moles of Ammonium Nitrate:
According to balance chemical equation;
1 mole of (NH₄)₂CO₃ produces = 2 moles of NH₄NO₃
So,
1.144 moles of (NH₄)₂CO₃ will produce = X moles of NH₄NO₃
Solving for X,
X = 2 moles × 1.144 moles ÷ 1 mole
X = 2.288 moles of NH₄NO₃
In each mole of carbon dioxide there will be one mole of O₂.
Let us calculate the moles of carbon dioxide gas present first
The conditions are NTP it means , Temperature = 293 K and P = 1 atm
We will use ideal gas equation
PV= nRT
Where
P = Pressure of gas = 1 atm
V= 112mL=0.112L
R= gas constant =0.0821 L atm /mol K
n = moles = ?
Putting values
moles = 0.00466
Thus moles of carbon dioxide will be 0.00466
The moles of O₂ = 0.00466
Answer:
I'm not completely sure but possibly (HCO³)
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The correct answer is Strontium-90.
Strontium-90 breaks down into yttrium-90.
Strontium-90 is a radioactive isotope of strontium. It undergoes β− decay into yttrium-90. A decay energy of 0.546 MeV is also released.
⁹⁰₃₈Sr -> ⁰₋₁e + ⁹⁰₃₉Yr
Beta particle has the charge and mass of an electron. Upon the release of a beta particle, the mass number of Sr remains unchanged but the atomic number of Sr increases by 1. As a result both Sr and Yt have mass number 90, however, Sr and Yt have atomic numbers 38 and 39 respectively.
