Hey! Apologies that I can’t make this look nice because I’m on mobile.
To simplify this, we can multiply the denominator by its conjugate. For a imaginary function (a+bi), its conjugate would be (a-bi), so we can apply that here to multiply both sides by (2-i)/(2-i). This works because it simplifies to one. Then, we have our fraction as 4*(2-i)/((2-i)(2+i))=(8-4i)/(4-i^2)=(8-4i)/5
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Answer:
no solution
Step-by-step explanation:
examples: 4^1 + 2 = 2^ 1 -1 and the answer is 6 = 1 which is not true. So its gonna be hard for them to have a solution.
Answer:
(18, ∞)
Step-by-step explanation:
(18, ∞) is the only option that works. if we ignore the "greater than" sign, and just set the function equal to -12, we see that x-10=-12 would give us x=-2. If we plug in -3 for x, we get -13, which is less than -12. if we plug in -1 for x, we get -11, which is greater than -12. Therefore, with the function only having one critical point (zero), we know that every value greater than -2 is a solution. Technically, the full solution would be (-2, ∞). however, the only answer available meeting the criteria would be (18, ∞).