Answer:
a. 2.4 ×109 N ⋅ m2/s
b. 48.3 N⋅s /m2
c. 8.00×104W
Explanation:
See Attached file for explanation
Answer:
Magnitude of the force on proton = F = 1.1085 × 10^-15 N
Explanation:
Charge on proton = q = 1.60 × 10^-19 C
Velocity of proton = V = 4.0 × 10^4 m/s
Magnetic field = B = 0.20 T
Angle between V and B = θ = 60
We know that,
F = qVBsin θ = (1.60 × 10^-19)( 4.0 × 10^4)( 0.20)sin(60)
F = 1.1085 × 10^-15 N
18 mililiter is equivilent to 0.0047551
Well, first of all, the car is not moving at a uniform velocity, because,
on a curved path, its direction is constantly changing. Its speed may
be constant, but its velocity isn't.
The centripetal force on a mass 'm' that keeps it on a circle with radius 'r' is
F = (mass) · (speed)² / (radius).
For this particular car, the force is
(2,000 kg) · (25 m/s)² / (80 m)
= (2,000 kg) · (625 m²/s²) / (80 m)
= (2,000 · 625 / 80) (kg · m / s²)
= 15,625 newtons .
The path followed by a projectile is called its <em>trajectory. (C)</em>
In the most common school situation<em> </em>... <u>with</u> gravity but <u>without</u> air resistance, the trajectory of a projectile is the shape of an inverted parabola (nose pointing up). That's the result of constant horizontal velocity and accelerated vertical velocity.
