Answer:
24
Step-by-step explanation:
The question is saying, how many three digit numbers can be made from the digits 3, 4, 6, and 7 but there can't be two of the same digit in them. For example 346 fits the requirements, but 776 doesn't, because it has two 7s.
Okay, on to the problem:
We can do one digit at a time.
First digit:
There are 4 digits that we can choose from. (3, 4, 6, and 7)
Second digit:
No matter which digit we chose for the first digit, there is only going to be 3 of them left, because we already chose one, and you can't repeat that same digit. So there are 3 options.
Third digit:
Using the same logic, there are only 2 options left.
We have 4 choices for the first digit, 3 choices for the second, and 2 for the third.
Hence, this is 4 * 3 * 2 = 24 three-digit numbers that can be made.
Answer:
( 11 -6)
( -5 6 )
Step-by-step explanation:
Multiply the first row of N by first column of M. This will give the first element in top row of the answer :-
-3*-2 + 1*5 = 11
Then multiply the first row in N by the second column of M to give the second element of the top row.
-3*0 + 1*-6 = -6
Then do a similar process with the second row in N.
Answer:
Of means multiply in math (most of the time).
So multiply.
2/5 x 7/10 = 14/50 divided by 2/2 = 7/25
Step-by-step explanation:
The first and crucial thing we want to take notice is that the lines DF and EG intersect at point H which creates 4 different triangles in the rhombus. The innermost angles of DGH and EFH are vertical angles and vertical angles are congruent. So if the angles of the triangles are congruent than the triangles themselves are congruent. This is supported by the vertical angles theorem.
Answer:
Step-by-step explanation:
Year on is 480 dollars and year two is 960 dollars