So if the measure of angle AMB = 90 so the another right triangle is formed which is ADM, since the it is a right triangle the legs are equal, then the lenght AD = DM and we can solve the length of AM
AM = sqrt( AD^2 + DM^2)
AM = sqrt( 6^2 + 6^2)
AM = 6sqrt(2)
now we can solve the length of AB
AB = sqrt ( AM^2 + MB^2)
AB = sqrt ( 6sqrt(2)^2 + 6sqrt(2)^2)
AB = 12
so the perimeter = 2(6) + 2(12) = 36
Answer:
D. 28.54
Step-by-step explanation:
To find the area of the shaded region, find the area of the circle and divide it in 4. This will the area of the portion with the triangle.
Now, find the area of the triangle and subtract the two. The resulting value will be the area of the shaded region.
Circle:
Divide by 4 for the area of the section with the triangle.
314/4 = 78.5
Triangle:
Subtract the two, 78.5 - 50 = 28.5.
The line through that point and the origin has a slope of -1. It is perpendicular to the line you want, so the line you want has slope +1. Its equation can be written as
.. y = (x -4) -4
or, in standard form
.. x - y = 8
Answer:
Since this means f of g so I will get the function g(x) and replace it with X in the function of f (x)
Maria got 21 correct.
Number wrong = Total - Number right
y = 25 - 21
y = 4
Maria got 4 wrong.
Hope this helps!