X = 5
AE and congruent to EC
B, A, D, C
or 2, 1.81, 1.799, 1.511
its simply just 102.
...................................................................................
(c+4/c^2+5c+6)/(3c^2+12c/2c^2+5c-3)= (c+4)/(c^2+5c+6) Multiplied by (2c^2+5c-3)/3c^2+12c= 2c^3+5c^2-3c+8c^2+20c-12/3c^4+12c^3+15c^3+60c^2+18c^2+72= 2c^3+13c^2+17c-12/3c^4+27c^3+78c^2+72c
