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2 years ago

What is an equivalent expression to 9(c+5)?

Mathematics

2 answers:

Vika [28.1K]2 years ago

8 0

Answer:

9c+45!

You only need to solve by using the distributive property.

9(c+5), is equal to 9(c)+9(5), or 9*c+9*5. Which can me simplified to 9c+45

Thepotemich [5.8K]2 years ago

4 0

9c + 45 because you factor the 9 into both c and 5

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Which expression could be used to determine the cost of a $40 video game after a 15 percent discount?

LUCKY_DIMON [66]

Answer: The required expression is,

$ 40(0.85)

Step-by-step explanation:

Given,

The original cost of the videogame = $ 40,

Discount percentage = 15%,

So, the amount of discount = 15% of 40

= (0.15)40 ( ∵ 1% = 0.01 )

Hence, the cost of the videogame = original cost - discount

= 40 - (0.15)40

= 40 (1-0.15)

= 40(0.85)

Which is the required expression .

5 0

2 years ago

Read 2 more answers

5.) How many, and what type of solutions does 2x^2 + 11x + 15 = 0 have?

-Dominant- [34]

Answer: A i think

Step-by-step explanation:

5 0

2 years ago

Consider the initial value problem y′+5y=⎧⎩⎨⎪⎪0110 if 0≤t<3 if 3≤t<5 if 5≤t<[infinity],y(0)=4. y′+5y={0 if 0≤t<311 i

rosijanka [135]

It looks like the ODE is

$y'+5y=\begin{cases}0&\text{for }0\le t$

with the initial condition of $y(0)=4$ .

Rewrite the right side in terms of the unit step function,

$u(t-c)=\begin{cases}1&\text{for }t\ge c\\0&\text{for }t$

In this case, we have

$\begin{cases}0&\text{for }0\le t$

The Laplace transform of the step function is easy to compute:

$\displaystyle\int_0^\infty u(t-c)e^{-st}\,\mathrm dt=\int_c^\infty e^{-st}\,\mathrm dt=\frac{e^{-cs}}s$

So, taking the Laplace transform of both sides of the ODE, we get

$sY(s)-y(0)+5Y(s)=\dfrac{e^{-3s}-e^{-5s}}s$

Solve for $Y(s)$ :

$(s+5)Y(s)-4=\dfrac{e^{-3s}-e^{-5s}}s\implies Y(s)=\dfrac{e^{-3s}-e^{-5s}}{s(s+5)}+\dfrac4{s+5}$

We can split the first term into partial fractions:

$\dfrac1{s(s+5)}=\dfrac as+\dfrac b{s+5}\implies1=a(s+5)+bs$

If $s=0$ , then $1=5a\implies a=\frac15$ .

If $s=-5$ , then $1=-5b\implies b=-\frac15$ .

$\implies Y(s)=\dfrac{e^{-3s}-e^{-5s}}5\left(\frac1s-\frac1{s+5}\right)+\dfrac4{s+5}$

$\implies Y(s)=\dfrac15\left(\dfrac{e^{-3s}}s-\dfrac{e^{-3s}}{s+5}-\dfrac{e^{-5s}}s+\dfrac{e^{-5s}}{s+5}\right)+\dfrac4{s+5}$

Take the inverse transform of both sides, recalling that

$Y(s)=e^{-cs}F(s)\implies y(t)=u(t-c)f(t-c)$

where $F(s)$ is the Laplace transform of the function $f(t)$ . We have

$F(s)=\dfrac1s\implies f(t)=1$

$F(s)=\dfrac1{s+5}\implies f(t)=e^{-5t}$

We then end up with

$y(t)=\dfrac{u(t-3)(1-e^{-5t})-u(t-5)(1-e^{-5t})}5+5e^{-5t}$

3 0

3 years ago

Original price : $82 <br> discount : 10% <br> sales price : ? <br> what does sales price equal ?

kozerog [31]

To find 10% of 82, you do 82*.1 so 8.2 is taken off the total.

So if we do 82-8.2 you get 73.8 as the sale price

Hope this helps

7 0

2 years ago

Read 2 more answers

What is the slope of the line that passes through the points (7, -9) <br>and (15, -29)?

vekshin1

answer: 4.75

Step-by-step explanation:

To find the slope, you divide the difference of the y-coordinates of 2 points on a line by the difference of the x-coordinates of those same 2 points. Which means, y1 - y2 / x1 - x2 = 29 - (-9) / 15 - 7

= 29 + 9 / 8

= 38/8

=4.75

6 0

1 year ago