Answer:
Hello
you're answer should be E.HOCH2CH2OH
hope this answer is correct
Answer:
3
Explanation:
metallic oxides are basic in nature.
Answer:
22.8 L
Explanation:
Step 1: Given data
- Moles of the gas (n): 1.35 mol
- Pressure of the gas (P): 1.30 atm
- Ideal gas constant (R): 0.0821 atm.L/mol.K
Step 2: Convert "T" to Kelvin
We will use the following expression.
K = °C + 273.15 = -6 + 273.15 = 267 K
Step 3: Calculate the volume of the gas
We will use the ideal gas equation.
P × V = n × R × T
V = n × R × T / P
V = 1.35 mol × (0.0821 atm.L/mol.K) × 267 K / 1.30 atm
V = 22.8 L
Answer:
Explanation:
Given that:
Half life = 14.0 days
Where, k is rate constant
So,
The rate constant, k = 0.04951 days⁻¹
Initial concentration [A₀] = 60.0 g
Time = 46.7 hrs
Considering, 1 hr = 0.041667 days
So, time = 1.9458 days
Using integrated rate law for first order kinetics as:
Where,
is the concentration at time t
So,