Step-by-step explanation:
5B+4F= $30.76
×3
15B+12F= $92.28
----------------------------
8B+6F= $48.28
×2
16B+12F= $96.56
----------------------------
Cost of one burger:
$97.56-$92.28= $4.28 (final ans)
Cost of one fries:
$30.76-5($4.28)= $9.36 (for 5 fries)
$9.36÷5= $1.87 (final ans)
Solution:
1) Add 80 to both sides
-np<60+80
2) Simplify 60+80 to 140
-np<140
3) Divide both sides by p
-n<\frac{140}{p}
4) Multiply both sides by -1
n>-\frac{140}{p}
Done!
Answer:
r = 9
Step-by-step explanation:
Given that c varies directly as (r + 1) then the equation relating them is
c = k(r + 1) ← k is the constant of variation
To find k use the condition c = 8 when r = 3, then
8 = k(3 + 1) = 4k ( divide both sides by 4 )
2 = k
c = 2(r + 1) ← equation of variation
When c = 20, then
20 = 2(r + 1) ← divide both sides by 2
10 = r + 1 ( subtract 1 from both sides )
9 = r
A. If the center plans to feed 700 people in 4 hours, then in order to find the average number of people the center is planning to feed each hour is 700/4 which is equal 175. So, the center is planning to feed 175 people per hour.
B. If during the first hour and a half, the center fed 270 people, find the remaining people to feed left: 700 - 270 = 430 people left to feed.
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Answer:
<u>1</u><u>2</u>
2
Step-by-step explanation:
(3,7)(5,19)
(x,y)(x,y)
<u>y2</u><u>(</u><u>1</u><u>9</u><u>)</u><u>-</u><u> </u><u>y1</u><u>(</u><u>7</u><u>)</u>
x2(5)-x1 (3)
formula. <u>y2-y1</u>
x2-x1
