We are asked to determine what happens to the values of
as
approaches
using values of
less than
AND using values of
greater than
.
<span>Observe from the graph that as </span>
approaches
from the left or the right, the values of
increase without bound.
Therefore, we know the following.
The minimum is the vertex
y=a(x-h)^2+k
(h,k) is vertex
given
(4,-8)
y=a(x-4)^2-8
find a
given
(2,0) and (6,0)
find a
0=a(2-4)^2-8
0=a(2)^2-8
0=4a-8
8=4a
divide 4
2=a
other one
0=a(6-4)^2-8
0=a(2)^2-8
0=4a-8
8=4a
divide 4
2=a
the function is
y=2(x-4)²-8 or expanded
y=2x^2-16x+24
Answer:
D) -21.3 > -32.1 answer true .