Using a binomial distribution considering there's a 30% chance it will rain on any of the three days:
<span>The probability of it raining on 0 days is (1)(0.7)(0.7)(0.7) = 34.3%. </span>
<span>The probability of it raining on 1 day is (3)(0.3)(0.7)(0.7) = 44.1%. </span>
<span>The probability of it raining on 2 days is (3)(0.3)(0.3)(0.7) = 18.9%. </span>
<span>The probability of it raining on 3 days is (1)(0.3)(0.3)(0.3) = 2.7%. </span>
<span>There's a 65.7% chance that it will rain at least once over the three-day period.</span>
1500 * 1/5
1500 * 0.2 = 300
300 * 12 = 3600
Javier contributes $3,600 a year to his savings.
Area of the base = 1/2 * 10 * 5sqrt3 = 25 sqrt3
Total surface area = 25 sqrt3 + 3 * 1/2 * 10 * slant height = 214.5
25 sqrt3 + 15h = 214.5
15h = 214.5 - 25 sqrt3
h = (214.5 - 25sqrt3() / 15
= 11.41 cm to nearest hundredth
Answer:
19.77% of average city temperatures are higher than that of Cairo
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean and standard deviation , the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question, we have that:
What percentage of average city temperatures are higher than that of Cairo?
This is 1 subtracted by the pvalue of Z when X = 21.4.
has a pvalue of 0.8023
1 - 0.8023 = 0.1977
19.77% of average city temperatures are higher than that of Cairo