Answer:
The correct answer is C.
Step-by-step explanation:
I took the test
Given:
The expression is .
To find:
The position of parentheses inserted in the expression to get the value 19
Step-by-step explanation:
We have,
Now,
There are more ways to apply the parenthesis, but we do not get 19.
And many more possibilities.
Therefore, the expression after inserting the parentheses is .
Answer:
m<N = 76°
Step-by-step explanation:
Given:
∆JKL and ∆MNL are isosceles ∆ (isosceles ∆ has 2 equal sides).
m<J = 64° (given)
Required:
m<N
SOLUTION:
m<K = m<J (base angles of an isosceles ∆ are equal)
m<K = 64° (Substitution)
m<K + m<J + m<JLK = 180° (sum of ∆)
64° + 64° + m<JLK = 180° (substitution)
128° + m<JLK = 180°
subtract 128 from each side
m<JLK = 180° - 128°
m<JLK = 52°
In isosceles ∆MNL, m<MLN and <M are base angles of the ∆. Therefore, they are of equal measure.
Thus:
m<MLN = m<JKL (vertical angles are congruent)
m<MLN = 52°
m<M = m<MLN (base angles of isosceles ∆MNL)
m<M = 52° (substitution)
m<N + m<M° + m<MLN = 180° (Sum of ∆)
m<N + 52° + 52° = 180° (Substitution)
m<N + 104° = 180°
subtract 104 from each side
m<N = 180° - 104°
m<N = 76°
Answer:
213 in base 4 = 124 in base 5
Step-by-step explanation:
First we convert base 4 to base 10
213 in base 4
2*42 + 1*41 + 3*40
32 + 4 + 3
39 in base 10
Now we convert base 10 to base 5
39/5
7/5 r = 4
1 r = 2
124 in base 5
Hence 213 in base 4 = 124 in base 5
Answer: The minimum reliability for the second stage be 0.979.
Step-by-step explanation:
Since we have given that
Probability for the overall rocket reliable for a successful mission = 97%
Probability for the first stage = 99%
We need to find the minimum reliability for the second stage :
So, it becomes:
P(overall reliability) = P(first stage ) × P(second stage)
Hence, the minimum reliability for the second stage be 0.979.