Hey there! :)
Answer:
C(-1) = -5.
Step-by-step explanation:
C(x) = -4x² + 4x + 3
Plug in -1 for x to solve for C(-1):
C(-1) = -4(-1)² + 4(-1) + 3
Simplify:
C(-1) = -4 + (-4) + 3
C(-1) = -5
Answer:
Problem 4 If the point (2, 2) is in the feasible set and the vertices of the feasible sct are (0,0), (0, 12). (6,18). (14, 16), and (18, 0), then determine the system of linear inequalities that created the feasible set. Show all the work that led you to you answer. (10 points) Problem 5 When Jack started his job working for an industrial manufacturing company, he contributed $100 at the end of each month into a savings account that earned 1.2 % interest compounded monthly for 8 years. At the end of the year, Jack was laid off. To help mect family expenses, Jack withdrew $285 from the savings account at the end of each month for 2 years. At the end of the second year of being unemployed, Jack found another job and started contributing $138 back into the savings account at the end of each month for the next six years. How much money would he have in the account at the end of the six years (after returning to work)? You may use the TVM Solver. Show all the necessary work that you need perform to arrive at the answer. (10 points)
Problem 5 When Jack started his job working for an industrial manufacturing company, he contributed $100 at the end of each month into a savings account that earned 1.2 % interest compounded monthly for 8 years. At the end of the 8th year, Jack was laid off. To help meet family expenses, Jack withdrew $285 from the savings account at the end of each month for 2 years. At the end of the second year of being unemployed, Jack found another job and started contributing $138 back into the savings account at the end of each month for the next six years. How much money would he have in the account at the end of the six years after returning to work)? You may use the TVM Solver. Show all the necessary work that you need perform to arrive at the answer. (10 points)
Answer:
a) =4.63 md=4.55 mo= 1.9 b) Sample Standard Deviation≈ 2.58 Coefficient of Variation=55.72% Sample Range=6.9
Step-by-step explanation:
a)
<u>Mean</u>
For the <u>Median</u>, we have to order the entries. So, ordering it goes:
1.9 1.9 2.3 3.9 5.2 5.7 7.3 8.8
Since we have even entries
mode
The mode for this data 1.9 1.9 2.3 3.9 5.2 5.7 7.3 8.8 is 1.9
b)
<u>Sample Standard Deviation</u>
Here it is the formula to calculate it:
<u>Coefficient of Variation</u>
CV is the quocient between sample Standard deviation over Mean and it is used to make comparisons.
<u>Range</u>
The difference between the highest and the lowest value of this sample
8.8-1.9=6.9
Answer:
The numerical length of EG is 20 units
Step-by-step explanation:
Here, we are told to determine the numerical length of EG
We are told in the question that point F is on the line segment EG
Thus, by mathematical conventions (
EG = EF + FG
inputing the values given in the question;
5x = 2x + 2x + 4
5x = 4x + 4
5x -4x = 4
x = 4
But EG = 5x
So EG = 5(4)
EG = 20 units