What is this number in standard form? (5×1,000)+(9×1)+(2×1/10)+(6×1/1,000)

Mathematics

1 answer:

mr Goodwill [35]2 years ago

5 0

Answer:

5009.206

Step-by-step explanation:

<u>The answer is </u><em><u>5009.206</u></em>. We see that the first portion of this question asks, "(5×1,000)+(9×1)". 5x1000 is 5000. 9x1 is 9. 5000+9= 5009. The second portion of this question asks for the numbers that go after the decimal. 2x1/10 is 2/10. 6x1/1000 is 6/1000. The decimal place stands for one. So we do .206. If the decimal stands for ones that means in this case the 2 is in the tenths place (like it should be since the question asks for 2/10) and the 6 is in the 1000 place (like it should be since the question asks for 6/1000). We add this up together and our answer is 5009.206. Hope this explanation helps! Happy learning!

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Rationalise the denominator of: -7/(√11 - √5)

tatuchka [14]

-7(sqrt(11)+sqrt(5))/6

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3 0

2 years ago

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PLEASE ANSWER ASAP!!

Rufina [12.5K]

Answer:

The instantaneous rate of increase of f(x) at $x_{0} = 3$ is 3.
One possible equation of this line is y = 3x - 16.
The line is tangent to the graph of y = f(x). The slope of the line is the same as the instantaneous rate of increase of f(x) at $x_{0} = 3$ .

Step-by-step explanation:

$\begin{aligned}&\lim_{h\to 0}{\frac{f(3+h)-f(h)}{h}}\\ =&\lim_{h\to 0}\frac{1}{h} \cdot [(3^{3} + 3 \times 3^{2}h +3\times 3h^{2} + h^{3})- 4(3^{2} + 2\times 3h + h^{2}) + 2 \\[-1em] &\phantom{\lim_{h\to 0}\frac{1}{h}\cdot []} -(3^{3} -4\times 3^{2} + 2)]\\ = &\lim_{h \to 0}\frac{h^{3} + 5h^{2} +3h}{h}\\=& \lim_{h \to 0}{h^{2}} + \lim_{h \to 0}{5h} + \lim_{h\to 0}{3}\\ =& 3\end{aligned}$ .

$f(3) = 3^{3} - 4\times 3^{2} + 2 =-7$ .

In other words, the graph of y = f(x) passes through the point (3, -7) where $x = 3$ .

The point-slope form of a line in a cartesian plane is:

$y - y_0 = m (x - x_0)$ .

For this line,

$(3, -7)$ is the point on the line, while

$3$ is the slope of the line.

The equation of this line will thus be

$y - (-7) = 3(x - 3)$ .

That's equivalent to

$y = 3x - 16$ .

Refer to the diagram attached. The line touches the graph of y = f(x) at x = 3 without crossing it. The line here is thus a tangent to the graph of y = f(x) at x = 3. The slope of the line represents the instantaneous rate of increase of f(x) at $x_{0} = 3$ .