Answer:
60 chickens
Step-by-step explanation:
We assume the 140 refers to the number animals (heads, noses, bodies, whatever). If all of those were chickens, there would be 280 legs. There are 160 legs more than that.
Since each pig that replaces a chicken adds 2 legs, there must be 160/2 = 80 pigs. That leaves 140 -80 = 60 chickens.
8 x 64 = (8 x 60) + (8 x 4)=
Answer:
Volume ≈ 33.33 cubic feet
Step-by-step explanation:
The question is:
<em>Find the volume of a right square pyramid with base square edges measuring 5 feet each and a height of the pyramid be 4 feet.</em>
<em />
So, the base is a square with side length 5 feet.
And the height of the pyramid is 4 feet.
The volume of a pyramid is given by the formula:
Where
a is the square base side length (given as 5)
h is the height of the pyramid (given as 4)
Now we substitute and find the value:
The volume is around 33.33 cubic feet
Answer:
127.17 cm²
Step-by-step explanation:
- Area of a semicircle: 1/2*π*r²
- π (pi) = 3.14
- r (radius) = d (diamater) / 2 => 18/2 = 9 cm
A = 1/2*π*r²
A = 1/2*3.14*9²
A = 1/2*3.14*81
A = 3.14*40.5
A = 127.17 cm²
Therefore, the area of the semicircle is 127.17 cm²
Hope this helps!
Consider the equation y = x^2. No matter what x happens to be, the result y will never be negative even if x is negative. Example: x = -3 leads to y = x^2 = (-3)^2 = 9 which is positive.
Since y is never negative, this means the inverse x = sqrt(y) has the right hand side never be negative. The entire curve of sqrt(x) is above the x axis except for the x intercept of course. Put another way, we cannot plug in a negative input into the square root function for this reason. This similar idea applies to any even index such as fourth roots or sixth roots.
Meanwhile, odd roots such as a cube root has its range extend from negative infinity to positive infinity. Why? Because y = x^3 can have a negative output. Going back to x = -3 we get y = x^3 = (-3)^3 = -27. So we can plug a negative value into the cube root to get some negative output. We can get any output we want, negative or positive. So the range of any radical with an odd index is effectively the set of all real numbers. Visually this produces graphs that have parts on both sides of the x axis.