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2 years ago

Simplify the expression below.

Mathematics

1 answer:

statuscvo [17]2 years ago

6 0

Answer:

(a)

Step-by-step explanation:

x^-4 + -4 + -4 + -4 + -4 + -4 = x^-24

hope it helps :)

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In 2018, the population will grow over 700,000.The population of a city in 2010 was 450,000 and was growing at a rate of 5% per

Firlakuza [10]

Answer:

The year is 2020.

Step-by-step explanation:

Let the number of years passed since 2010 to reach population more than 7000000 be 'x'.

Given:

Initial population is, $P_0=450,000$

Growth rate is, $r=5\%=0.05$

Final population is, $P=700,000$

A population growth is an exponential growth and is modeled by the following function:

$P=P_0(1+r)^x$

Taking log on both sides, we get:

$\log(P)=\log(P_0(1+r)^x)\\\log P=\log P_0+x\log (1+r)\\x\log (1+r)=\log P-\log P_0\\x\log(1+r)=\log(\frac{P}{P_0})\\x=\frac{\log(\frac{P}{P_0})}{\log(1+r)}$

Plug in all the given values and solve for 'x'.

$x=\frac{\log(\frac{700,000}{450,000})}{\log(1+0.05)}\\x=\frac{0.192}{0.021}=9.13\approx 10$

So, for $x > 9.13$ , the population is over 700,000. Therefore, from the tenth year after 2010, the population will be over 700,000.

Therefore, the tenth year after 2010 is 2020.

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2 years ago

Select the correct answer.

Pani-rosa [81]

Answer:

Step-by-step explanation:

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2 years ago

2/3xd=10/9 what is d

lisabon 2012 [21]

Answer:d=5/3x

Step-by-step explanation:

Let's solve for d.

(2/3x)(d)=10/9

Step 1: Divide both sides by (2x)/3.

2/3dx / 2x/3=10/9 / 2x/3

d=5/3x

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2 years ago

How do u do this please

blagie [28]

Answer: In number 1 the answer is 2. Number 2 the answer is 7. Number 3 you read the problem as 4 x 4 x 4 or 4 to the 3rd. For number 4 it's 2x2x2x2x2x2x2 or 2 to the 7th power. Number 5 is right. For number 6 B. is 5. C is 6

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Step-by-step explanation:

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2 years ago

What's the difference between perpendicular bisectors and altitudes

FromTheMoon [43]

Perpendicular bisectors help you find the centroid; altitudes help find the orthocenter. This is all in a triangle.

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2 years ago