4x³ - 6x² + 10x - 15
2x²(2x) - 2x²(3) + 5(2x) - 5(3)
2x²(2x - 3) + 5(2x - 3)
(2x² + 5)(2x - 3)
The answer is B.
Answer:
95% confidence interval for the proportion of students supporting the fee increase is [0.767, 0.815]. Option C
Step-by-step explanation:
The confidence interval for a proportion is given as [p +/- margin of error (E)]
p is sample proportion = 870/1,100 = 0.791
n is sample size = 1,100
confidence level (C) = 95% = 0.95
significance level = 1 - C = 1 - 0.95 = 0.05 = 5%
critical value (z) at 5% significance level is 1.96.
E = z × sqrt[p(1-p) ÷ n] = 1.96 × sqrt[0.791(1-0.791) ÷ 1,100] = 1.96 × 0.0123 = 0.024
Lower limit of proportion = p - E = 0.791 - 0.024 = 0.767
Upper limit of proportion = p + E = 0.791 + 0.024 = 0.815
95% confidence interval for the proportion of students supporting the fee increase is between a lower limit of 0.767 and an upper limit of 0.815.
For a 10 month period the last term is 10 and the series sum is 55. For a 15 month period the last term is 15 and the sum is 120. For a 20 month period the last term is 20.
If u want the sum then it is 210.
Hope this helps you!
