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2 years ago

8

What is the answer to this how to work it

1 answer:

Anna007 [38]2 years ago

7 0

9514 1404 393

Answer:

(A) -7

Step-by-step explanation:

The function is continuous if you can draw its graph without lifting your pencil. In this case, that means each of the piecewise function definitions must have the same value at x=3.

x^2 +2 = 6x +k . . . . . must be true at x=3

3^2 +2 = 6(3) +k . . . . substitute 3 for x

9 +2 -18 = k . . . . . . . . subtract 18

k = -7 . . . . . . . simplify

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HELP PLS’ Suppose you roll a die. Find the probability of the given event. Simplify your answer.

NikAS [45]

The answer is 2) 2/3

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2 years ago

A line contains the points (-5, 3) and (0, -7). What is the equation of this line in slope-intercept form?

pychu [463]

Answer:

D. y = –2x – 7

Step-by-step explanation:

First, find the <em>rate</em><em> </em><em>of change</em><em> </em>[<em>slope</em>]:

-y₁ + y₂\-x₁ + x₂ = m

$- \frac{3 - 7}{5 + 0} = -\frac{10}{5} = -2$

In this case, the y-intercept of [0, -7] is ALREADY given to you, so we would not have to go further in this case.

I am joyous to assist you anytime.

8 0

2 years ago

Read 2 more answers

A student on a piano stool rotates freely with an angular speed of 2.85 rev/s . The student holds a 1.50 kg mass in each outstre

Vlad1618 [11]

Answer:r'=0.327 m

Step-by-step explanation:

Given

$N=2.85 rev/s$

angular velocity $\omega =2\pi N=17.90 rad/s$

mass of objects $m=1.5 kg$

distance of objects from stool $r_1=0.789 m$

Combined moment of inertia of stool and student $=5.53 kg.m^2$

Now student pull off his hands so as to increase its speed to 3.60 rev/s

$\omega _2=2\pi N_2$

$\omega _2=2\pi 3.6=22.62 rad/s$

Initial moment of inertia of two masses $I_0=2mr_^2$

$I_0=2\times 1.5\times (0.789)^2=1.867$

After Pulling off hands so that r' is the distance of masses from stool

$I_0'=2\times 1.5\times (r')^2$

Conserving angular momentum

$I_1\omega =I_2\omega _2$

$(5.53+1.867)\cdot 17.90=(5.53+I_o')\cdot 22.62$

$I_0'=1.397\times 0.791$

$I_0'=5.851$

$5.53+2\times 1.5\times (r')^2=5.851$

$2\times 1.5\times (r')^2=0.321$

$r'^2=0.107009$

$r'=0.327 m$

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2 years ago

In a sample with m = 40 and s = 8, what is the z-score corresponding to x = 38?

Alika [10]

Z = (x - m)/s
z = (38-40)/8
z = -2/8
z = -1/4
z = -0.25

The z score is -0.25

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2 years ago

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.3x+.03x+.003x+.0003x+.00003x=3<br> solve for x

Lemur [1.5K]

First, you can combine all of the terms involving x:
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0.33333x = 3
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x = 9.0000900009…
x ≈ 9
Hope this helps! :)

3 0

2 years ago