Answer:
The efficiency rating of the jack is 0.067.
Explanation:
We have, a person applies a force of 200 N over 1.5 m to a jack. The jack exerts a 1000-N force on a car a distance of 0.02 m.
It is required to find the the efficiency rating of the jack. It is equal to the ratio of output work to the ratio of input work. So,
Thus, the efficiency rating of the jack is 0.067.
<u>Conversion Factors:</u>
1.61 km = 1 mile
60 sec = 1 min
60 min = 1 hour
<u />
Use dimensional analysis to solve.
× × × ×
= 36 miles/hour
If done properly, you should be left with the units <em>miles/hour</em>
<em />
I think the answer is C. Hope this helped.
Answer:
1. analyze the samples while they are frozen
stuff can react differently when it's colder
hope I could help good luck