Answer:
Explanation:
given.
magnification(m) = 400 x
focal length (f_0)= 0.6 cm
distance between eyepiece and lens (L)= 16 cm
Near point (N) = 25 cm
focal length of the eyepiece (f_e)= ?
using equation
Answer:
b. 0.25cm
Explanation:
You can solve this question by using the formula for the position of the fringes:
m: order of the fringes
lambda: wavelength 500nm
D: distance to the screen 5 m
d: separation of the slits 1mm=1*10^{-3}m
With the formula you can calculate the separation of two adjacent slits:
hence, the aswer is 0.25cm
Answer:
S = 1/2 Vo t + 1/2 a t^2 = d time for particle to travel distance d
F = E q force acting on particle
a = F / m = E q / m
d = Vo t + E q / (2 m) t^2
One would need to solve the quadratic equation shown to find the time t
t^2 + (2 m) / E q * V0 t - (2 m) / E q * d = 0
or t^2 + A V0 t - A d = 0 where A = (2 m) / E q