All categories

2 years ago

3. Max wants to spend at most $89 on his friend's birthday gifts. He already bought her a $34 video

Mathematics

1 answer:

wariber [46]2 years ago

7 0

Answer:

Step-by-step explanation:

Answer:

The Inequality representing money she can still spend on her friend birthday gift is .

Jordan can still spend at most $30 on her friends birthday gift.

Step-by-step explanation:

Given:

Total money need to spend at most = $45

Money spent on Yoga ball = $15

We need to find how much money she can still spend on her friend birthday gift.

Solution:

Let the money she can still spend on her friend birthday gift be 'x'.

So we can say that;

Money spent on Yoga ball plus money she can still spend on her friend birthday gift should be less than or equal to Total money need to spend.

framing in equation form we get;

The Inequality representing money she can still spend on her friend birthday gift is .

On solving the the above Inequality we get;

we will subtract both side by 15 using subtraction property of Inequality.

Hence Jordan can still spend at most $30 on her friends birthday gift.

You might be interested in

A storage shed is to be built in the shape of a (closed) box with a square base. It is to have a volume of 150 cubic feet. The c

Alenkinab [10]

Answer:

$C(s) = 6s^2 + \dfrac{1500}{s}\\\text{where s is the side of base.}$

Step-by-step explanation:

We are given the following in the question:

A storage shed is to be built in the shape of a (closed) box with a square base.

Volume = 150 cubic feet

Let s be the edge of square base and h be the height.

Volume of cuboid =

$l\times b\times h$

where l is the length, b is the base and h is the height.

Volume of box =

$s^2h = 150\\\\h = \dfrac{150}{s^2}$

Area of base =

$\text{side}\times \text{side} = s^2$

Cost of concrete for the base = $4

Cost of base($) = $4s^2$

Area of roof =

$\text{side}\times \text{side} = s^2$

Cost of material for the roof = $2

Cost of roof ($) = $2s^2$

Area of 4 walls =

$4\times (sh)\\=4sh$

Cost of material for the side = $2.50

Cost of material of side($) =

$2.50\times 4s(\dfrac{150}{s^2})\\\\=\dfrac{1500}{s}$

Total cost

= Cost of base + Cost of 4 sides + Cost of roof

$C(s) = 4s^2 + \dfrac{1500}{s} + 2s^2\\\\C(s) = 6s^2 + \dfrac{1500}{s}$

is the required cost function.

5 0

2 years ago

Help.........................

garri49 [273]

<h3>Answer: Choice A</h3>

$x^2\left(\sqrt[4]{x^2}\right)$

=====================================================

Explanation:

The fourth root of x is the same as x^(1/4)

I.e,

$\sqrt[4]{x} = x^{1/4}$

The same applies to x^10 as well

$\sqrt[4]{x^{10}} = \left(x^{10}\right)^{1/4}$

Multiply the exponents 10 and 1/4 to get 10/4

$\sqrt[4]{x^{10}} = \left(x^{10}\right)^{1/4} = x^{10*1/4} = x^{10/4}$

$\sqrt[4]{x^{10}} = x^{10/4}$

-----------------------

If we have an expression in the form x^(m/n), with m > n, then we can simplify it into an equivalent form as shown below

$x^{m/n} = x^a\sqrt[n]{x^b}$

The 'a' and 'b' are found through dividing m/n

m/n = a remainder b

'a' is the quotient, b is the remainder

-----------------------

The general formula can easily be confusing, so let's replace m and n with the proper numbers. In this case, m = 10 and n = 4

m/n = 10/4 = 2 remainder 2

We have a = 2 and b = 2

$x^{m/n} = x^a\sqrt[n]{x^b}$

turns into

$x^{10/4} = x^2\sqrt[4]{x^2}$

which means

$\sqrt[4]{x^{10}} = {x^2} \sqrt[4]{x^2}$

7 0

2 years ago

What do you set each term equal to in order to solve for all of the "roots" of a function? No links please :)

Citrus2011 [14]

Answer:

Solving quadratic equations can be difficult, but luckily there are several different methods that we can use depending on what type of quadratic that we are trying to solve. The four methods of solving a quadratic equation are factoring, using the square roots, completing the square and the quadratic formula.

Step-by-step explanation:

can you mark me brainliest

3 0

2 years ago

Help!!!! Somebody help me solve these questions please

kykrilka [37]

Step-by-step explanation:

Area of a trapezium = SOPS/2 × ph

Sops is the sum of 4+10 = 14

14/2 is 7. 7×4 = 28

A = 28cm²

Area = L×W

10×6= 60cm²

5 0

2 years ago

Read 2 more answers

Can anyone help me find the area of these two pls ?

Rasek [7]

13: 72.25
14: 52
For 14, you need to split the figure into a triangle and rectangle.

5 0

1 year ago